760. Find Anagram Mappings
Given two lists
Aand B, and B is an anagram of A. B is an anagram of A means B is made by randomizing the order of the elements in A.
We want to find an index mapping
P, from A to B. A mapping P[i] = j means the ith element in A appears in B at index j.
These lists
A and B may contain duplicates. If there are multiple answers, output any of them.
For example, given
A = [12, 28, 46, 32, 50] B = [50, 12, 32, 46, 28]
[1, 4, 3, 2, 0]as
P[0] = 1 because the 0th element of A appears at B[1], and P[1] = 4 because the 1st element of A appears at B[4], and so on.
Note:
A, Bhave equal lengths in range[1, 100].A[i], B[i]are integers in range[0, 10^5].
Python 3 solution:
class Solution:
def anagramMappings(self, A, B):
"""
:type A: List[int]
:type B: List[int]
:rtype: List[int]
"""
return [B.index(i) for i in A]
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